numpy.strings.count#

strings.count(a, sub, start=0, end=None)[source]#

Returns an array with the number of non-overlapping occurrences of substring sub in the range [start, end).

Parameters:

aarray-like, with StringDType, bytes_, or str_ dtype

subarray-like, with StringDType, bytes_, or str_ dtype

The substring to search for.

start, endarray_like, with any integer dtype

The range to look in, interpreted as in slice notation.

Returns:

yndarray

Output array of ints

See also

str.count

Examples

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>>> import numpy as np
>>> c = np.array(['aAaAaA', '  aA  ', 'abBABba'])
>>> c
array(['aAaAaA', '  aA  ', 'abBABba'], dtype='<U7')
>>> np.strings.count(c, 'A')
array([3, 1, 1])
>>> np.strings.count(c, 'aA')
array([3, 1, 0])
>>> np.strings.count(c, 'A', start=1, end=4)
array([2, 1, 1])
>>> np.strings.count(c, 'A', start=1, end=3)
array([1, 0, 0])

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