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leetcode/src/sameTree/sameTree.cpp at master · AndyleeSharp/leetcode · GitHub
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//
Source : https://oj.leetcode.com/problems/same-tree/
//
Author : Hao Chen
//
Date : 2014-06-27
/*
*********************************************************************************
*
* Given two binary trees, write a function to check if they are equal or not.
*
* Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
*
*
*********************************************************************************
*/
/*
*
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class
Solution
{
public:
Solution
(){
srand
(
time
(
NULL
));
}
bool
isSameTree
(TreeNode *p, TreeNode *q) {
if
(
random
()%
2
){
return
isSameTree1
(p, q);
}
return
isSameTree2
(p, q);
}
bool
isSameTree1
(TreeNode *p, TreeNode *q) {
if
(!p && !q)
return
true
;
if
(!p || !q)
return
false
;
return
(p->
val
== q->
val
) &&
isSameTree
(p->
left
, q->
left
) &&
isSameTree
(p->
right
, q->
right
);
}
bool
isSameTree2
(TreeNode *p, TreeNode *q) {
queue<TreeNode*> q1, q2;
q1.
push
(p);
q2.
push
(q);
while
(q1.
size
()>
0
&& q2.
size
()>
0
){
TreeNode* p1 = q1.
front
();
q1.
pop
();
TreeNode* p2 = q2.
front
();
q2.
pop
();
if
(!p1 && !p2)
continue
;
if
(!p1 || !p2)
return
false
;
if
( p1->
val
!= p2->
val
) {
return
false
;
}
q1.
push
(p1->
left
);
q2.
push
(p2->
left
);
q1.
push
(p1->
right
);
q2.
push
(p2->
right
);
}
return
true
;
}
};
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