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JavaArithmetic/src/sort/QuickSort.java at master · Edwardlinge/JavaArithmetic · GitHub
Edwardlinge
JavaArithmetic
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sort
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QuickSort.java
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JavaArithmetic
/
src
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sort
/
QuickSort.java
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package
sort
;
import
java
.
util
.
Stack
;
/**
* Created by ozc on 2018/3/17.
*
* @author ozc
* @version 1.0
*/
public
class
QuickSort
{
public
static
void
main
(
String
[]
args
) {
//int[] arr = {1, 4, 5, 67, 2, 7, 8, 6, 9, 44, 34, 5, 5, 2, 34, 5, 62, 42, 1, 1324, 2346};
int
[]
arr
= {
23
,
34
,
33
,
56
,
45
};
quickSort
(
arr
,
0
,
arr
.
length
-
1
);
System
.
out
.
println
(
"Java3y "
+
arr
);
}
/**
* 快速排序
*
* @param arr
* @param L 指向数组第一个元素
* @param R 指向数组最后一个元素
*/
public
static
void
quickSort
(
int
[]
arr
,
int
L
,
int
R
) {
int
i
=
L
;
int
j
=
R
;
//支点
int
pivot
=
arr
[(
L
+
R
) /
2
];
//左右两端进行扫描，只要两端还没有交替，就一直扫描
while
(
i
<=
j
) {
//寻找直到比支点大的数
while
(
pivot
>
arr
[
i
])
i
++;
//寻找直到比支点小的数
while
(
pivot
<
arr
[
j
])
j
--;
//此时已经分别找到了比支点小的数(右边)、比支点大的数(左边)，它们进行交换
if
(
i
<=
j
) {
int
temp
=
arr
[
i
];
arr
[
i
] =
arr
[
j
];
arr
[
j
] =
temp
;
i
++;
j
--;
}
}
//上面一个while保证了第一趟排序支点的左边比支点小，支点的右边比支点大了。
//“左边”再做排序，直到左边剩下一个数(递归出口)
if
(
L
<
j
)
quickSort
(
arr
,
L
,
j
);
//“右边”再做排序，直到右边剩下一个数(递归出口)
if
(
i
<
R
)
quickSort
(
arr
,
i
,
R
);
}
//-----------------Stack方式实现快速排序
public
static
void
print
(
int
[]
arr
) {
for
(
int
n
=
0
;
n
<
arr
.
length
;
n
++) {
System
.
out
.
print
(
arr
[
n
] +
" "
);
}
System
.
out
.
println
();
}
public
static
void
fun
(
int
[]
a
,
int
low
,
int
high
) {
Stack
<
Integer
>
stack
=
new
Stack
<>();
if
(
low
<
high
) {
stack
.
add
(
low
);
stack
.
add
(
high
);
while
(!
stack
.
isEmpty
()) {
int
hi
=
stack
.
pop
();
int
lo
=
stack
.
pop
();
int
key
=
partition
(
a
,
lo
,
hi
);
if
(
lo
<
key
-
1
) {
stack
.
push
(
lo
);
stack
.
push
(
key
-
1
);
}
if
(
hi
>
key
) {
stack
.
push
(
key
+
1
);
stack
.
push
(
hi
);
//这样，最后入栈的就是key右边的部分，则下一次循环先处理key右边的部分
}
}
}
}
public
static
int
partition
(
int
[]
a
,
int
low
,
int
high
) {
// 选第一个元素作为key
int
key
=
a
[
low
];
while
(
low
<
high
) {
// 右边找到比key还要小的
while
(
a
[
high
] >=
key
&&
low
<
high
) {
high
--;
}
a
[
low
] =
a
[
high
];
// 左边找到比key要大的
while
(
a
[
low
] <=
key
&&
low
<
high
) {
//小于于等于key的数组元素不需要移动
low
++;
}
a
[
high
] =
a
[
low
];
}
a
[
low
] =
key
;
print
(
a
);
return
low
;
}
}
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