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LeetCode-Solutions/MySQL/triangle-judgement.sql at master · HappyCoderGit/LeetCode-Solutions · GitHub
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triangle-judgement.sql
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#
Time: O(n)
#
Space: O(1)
SELECT
*
,
IF (x
+
y
>
z
AND
x
+
z
>
y
AND
y
+
z
>
x,
"
Yes
"
,
"
No
"
)
AS
triangle
FROM
triangle;
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