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leetcode/problems/src/array/NextGreaterElementI.java at master · KindleBooks66/leetcode · GitHub
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array
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NextGreaterElementI.java
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src
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array
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NextGreaterElementI.java
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package
array
;
/**
* Created by gouthamvidyapradhan on 09/02/2018. You are given two arrays (without duplicates) nums1
* and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for
* nums1's elements in the corresponding places of nums2.
*
* <p>The Next Greater Number of a number x in nums1 is the first greater number to its right in
* nums2. If it does not exist, output -1 for this number.
*
* <p>Example 1: Input: nums1 = [4,1,2], nums2 = [1,3,4,2]. Output: [-1,3,-1] Explanation: For
* number 4 in the first array, you cannot find the next greater number for it in the second array,
* so output -1. For number 1 in the first array, the next greater number for it in the second array
* is 3. For number 2 in the first array, there is no next greater number for it in the second
* array, so output -1. Example 2: Input: nums1 = [2,4], nums2 = [1,2,3,4]. Output: [3,-1]
* Explanation: For number 2 in the first array, the next greater number for it in the second array
* is 3. For number 4 in the first array, there is no next greater number for it in the second
* array, so output -1. Note: All elements in nums1 and nums2 are unique. The length of both nums1
* and nums2 would not exceed 1000.
*/
public
class
NextGreaterElementI
{
/**
* Main method
*
* @param args
* @throws Exception
*/
public
static
void
main
(
String
[]
args
)
throws
Exception
{
int
[]
A
= {
4
,
1
,
2
};
int
[]
B
= {
1
,
3
,
4
,
2
};
int
[]
result
=
new
NextGreaterElementI
().
nextGreaterElement
(
A
,
B
);
System
.
out
.
println
(
result
);
}
public
int
[]
nextGreaterElement
(
int
[]
nums1
,
int
[]
nums2
) {
int
[]
result
=
new
int
[
nums1
.
length
];
for
(
int
i
=
0
;
i
<
nums1
.
length
;
i
++) {
int
n
=
nums1
[
i
];
boolean
found
=
false
;
int
nF
=
0
;
for
(
int
j
=
0
;
j
<
nums2
.
length
;
j
++) {
if
(
nums2
[
j
] ==
n
) {
found
=
true
;
}
if
(
found
) {
if
(
nums2
[
j
] >
n
) {
nF
=
nums2
[
j
];
break
;
}
}
}
if
(
found
) {
result
[
i
] =
nF
;
}
else
{
result
[
i
] = -
1
;
}
}
return
result
;
}
}
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