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leetcode/problems/src/string/ReplaceWords.java at master · KindleBooks66/leetcode · GitHub
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string
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ReplaceWords.java
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ReplaceWords.java
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package
string
;
import
java
.
util
.
Arrays
;
import
java
.
util
.
HashMap
;
import
java
.
util
.
List
;
import
java
.
util
.
Map
;
import
java
.
util
.
stream
.
Stream
;
/**
* Created by gouthamvidyapradhan on 04/04/2019 In English, we have a concept called root, which can
* be followed by some other words to form another longer word - let's call this word successor. For
* example, the root an, followed by other, which can form another word another.
*
* <p>Now, given a dictionary consisting of many roots and a sentence. You need to replace all the
* successor in the sentence with the root forming it. If a successor has many roots can form it,
* replace it with the root with the shortest length.
*
* <p>You need to output the sentence after the replacement.
*
* <p>Example 1:
*
* <p>Input: dict = ["cat", "bat", "rat"] sentence = "the cattle was rattled by the battery" Output:
* "the cat was rat by the bat"
*
* <p>Note:
*
* <p>The input will only have lower-case letters. 1 <= dict words number <= 1000 1 <= sentence
* words number <= 1000 1 <= root length <= 100 1 <= sentence words length <= 1000
*
* <p>Solution: O(w + S) where w is the max length of each word in the dictionary and S is the
* length of the string. Add all the words in the dictionary to a trie and evaluate each word in the
* string to check if it matches any path in the trie. Terminate the search as soon as a leaf node
* in the trie has been reached.
*/
public
class
ReplaceWords
{
class
Trie
{
private
Map
<
Character
,
Trie
>
map
;
/** Initialize your data structure here. */
public
Trie
() {
map
=
new
HashMap
<>();
}
/** Inserts a word into the trie. */
public
void
insert
(
String
word
) {
if
(
word
!=
null
) {
add
(
0
,
word
,
word
.
length
());
}
}
public
String
find
(
String
s
) {
return
search
(
this
,
s
,
0
,
new
StringBuilder
());
}
private
void
add
(
int
i
,
String
word
,
int
length
) {
if
(
i
<
length
) {
char
c
=
word
.
charAt
(
i
);
Trie
subTrie
=
map
.
get
(
c
);
if
(
subTrie
==
null
) {
subTrie
=
new
Trie
();
map
.
put
(
c
,
subTrie
);
}
subTrie
.
add
(
i
+
1
,
word
,
length
);
}
else
map
.
put
(
null
,
new
Trie
());
// use null to indicate end of string
}
private
String
search
(
Trie
curr
,
String
s
,
int
i
,
StringBuilder
sb
) {
if
(
s
.
length
() ==
i
)
return
sb
.
toString
();
else
{
Trie
subTrie
=
curr
.
map
.
get
(
s
.
charAt
(
i
));
if
(
subTrie
==
null
) {
return
curr
.
map
.
containsKey
(
null
) ?
sb
.
toString
() :
""
;
}
else
{
sb
.
append
(
s
.
charAt
(
i
));
if
(
subTrie
.
map
.
containsKey
(
null
))
return
sb
.
toString
();
return
search
(
subTrie
,
s
,
i
+
1
,
sb
);
}
}
}
}
/**
* Main method
*
* @param args
*/
public
static
void
main
(
String
[]
args
) {
List
<
String
>
words
=
Arrays
.
asList
(
"a"
,
"aa"
,
"aaa"
);
String
sentence
=
"aa aa"
;
System
.
out
.
println
(
new
ReplaceWords
().
replaceWords
(
words
,
sentence
));
}
public
String
replaceWords
(
List
<
String
>
dict
,
String
sentence
) {
Trie
root
=
new
Trie
();
dict
.
forEach
(
root
::
insert
);
String
[]
words
=
sentence
.
split
(
" "
);
StringBuilder
result
=
new
StringBuilder
();
Stream
.
of
(
words
)
.
map
(
w
-> {
String
s
=
root
.
find
(
w
);
return
s
.
isEmpty
() ?
w
.
concat
(
" "
) :
s
.
concat
(
" "
);
})
.
forEach
(
result
::
append
);
return
result
.
toString
().
trim
();
}
}
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