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LeetCode/src/main/java/L0139_WordBreak.java at master · LjyYano/LeetCode · GitHub
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java
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L0139_WordBreak.java
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LeetCode
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L0139_WordBreak.java
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/**
* https://leetcode.cn/problems/word-break/
*
* 题目描述:
* 给你一个字符串 s 和一个字符串列表 wordDict 作为字典。请你判断是否可以利用字典中出现的单词拼接出 s 。
*
* 注意:不要求字典中出现的单词全部都使用,并且字典中的单词可以重复使用。
*
* 示例 1:
* 输入: s = "leetcode", wordDict = ["leet", "code"]
* 输出: true
* 解释: 返回 true 因为 "leetcode" 可以由 "leet" 和 "code" 拼接成。
*
* 示例 2:
* 输入: s = "applepenapple", wordDict = ["apple", "pen"]
* 输出: true
* 解释: 返回 true 因为 "applepenapple" 可以由 "apple" "pen" "apple" 拼接成。
* 注意,你可以重复使用字典中的单词。
*
* 示例 3:
* 输入: s = "catsandog", wordDict = ["cats", "dog", "sand", "and", "cat"]
* 输出: false
*
* 提示:
* - 1 <= s.length <= 300
* - 1 <= wordDict.length <= 1000
* - 1 <= wordDict[i].length <= 20
* - s 和 wordDict[i] 仅由小写英文字母组成
* - wordDict 中的所有字符串 互不相同
*/
import
java
.
util
.*;
public
class
L0139_WordBreak
{
public
boolean
wordBreak
(
String
s
,
List
<
String
>
wordDict
) {
// 将字典转换为 Set,提高查找效率
Set
<
String
>
wordSet
=
new
HashSet
<>(
wordDict
);
// dp[i] 表示字符串 s 的前 i 个字符是否可以被拆分成字典中的单词
boolean
[]
dp
=
new
boolean
[
s
.
length
() +
1
];
// 空字符串可以被拆分
dp
[
0
] =
true
;
// 遍历每个位置,判断是否可以拆分
for
(
int
i
=
1
;
i
<=
s
.
length
();
i
++) {
// 尝试以当前位置为结尾,判断前面的子串是否可以拆分
for
(
int
j
=
0
;
j
<
i
;
j
++) {
// 如果前 j 个字符可以被拆分,且剩余部分在字典中存在
if
(
dp
[
j
] &&
wordSet
.
contains
(
s
.
substring
(
j
,
i
))) {
dp
[
i
] =
true
;
break
;
}
}
}
return
dp
[
s
.
length
()];
}
public
static
void
main
(
String
[]
args
) {
L0139_WordBreak
solution
=
new
L0139_WordBreak
();
// 测试用例 1
String
s1
=
"leetcode"
;
List
<
String
>
wordDict1
=
Arrays
.
asList
(
"leet"
,
"code"
);
System
.
out
.
println
(
"测试用例 1:"
);
System
.
out
.
println
(
"输入: s =
\"
"
+
s1
+
"
\"
, wordDict = "
+
wordDict1
);
System
.
out
.
println
(
"输出: "
+
solution
.
wordBreak
(
s1
,
wordDict1
));
System
.
out
.
println
();
// 测试用例 2
String
s2
=
"applepenapple"
;
List
<
String
>
wordDict2
=
Arrays
.
asList
(
"apple"
,
"pen"
);
System
.
out
.
println
(
"测试用例 2:"
);
System
.
out
.
println
(
"输入: s =
\"
"
+
s2
+
"
\"
, wordDict = "
+
wordDict2
);
System
.
out
.
println
(
"输出: "
+
solution
.
wordBreak
(
s2
,
wordDict2
));
System
.
out
.
println
();
// 测试用例 3
String
s3
=
"catsandog"
;
List
<
String
>
wordDict3
=
Arrays
.
asList
(
"cats"
,
"dog"
,
"sand"
,
"and"
,
"cat"
);
System
.
out
.
println
(
"测试用例 3:"
);
System
.
out
.
println
(
"输入: s =
\"
"
+
s3
+
"
\"
, wordDict = "
+
wordDict3
);
System
.
out
.
println
(
"输出: "
+
solution
.
wordBreak
(
s3
,
wordDict3
));
}
}
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