algorithms/algorithms/stack/simplify_path.py at master · NiklasBeierl/algorithms · GitHub

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"""

Given an absolute path for a file (Unix-style), simplify it.

For example,

path = "/home/", => "/home"

path = "/a/./b/../../c/", => "/c"

* Did you consider the case where path = "/../"?

In this case, you should return "/".

* Another corner case is the path might contain multiple slashes '/' together,

such as "/home//foo/". In this case, you should ignore redundant

slashes and return "/home/foo".

"""

def simplify_path(path):

"""

:type path: str

:rtype: str

"""

skip = {'..', '.', ''}

stack = []

paths = path.split('/')

for tok in paths:

if tok == '..':

if stack:

stack.pop()

elif tok not in skip:

stack.append(tok)

return '/' + '/'.join(stack)

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