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| Original file line number | Diff line number | Diff line change | |
|---|---|---|---|
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| 1 | + # Returns index of x in arr if present, else -1 | ||
| 2 | + | ||
| 3 | + def binary_search(arr, low, high, x): | ||
| 4 | + | ||
| 5 | + if high >= low: | ||
| 6 | + mid = (high + low) // 2 | ||
| 7 | + | ||
| 8 | + | ||
| 9 | + | ||
| 10 | + # If element is present at the middle itself | ||
| 11 | + | ||
| 12 | + if arr[mid] == x: | ||
| 13 | + | ||
| 14 | + return mid | ||
| 15 | + | ||
| 16 | + | ||
| 17 | + | ||
| 18 | + # If element is smaller than mid, then it can only | ||
| 19 | + | ||
| 20 | + # be present in left subarray | ||
| 21 | + | ||
| 22 | + elif arr[mid] > x: | ||
| 23 | + | ||
| 24 | + return binary_search(arr, low, mid - 1, x) | ||
| 25 | + | ||
| 26 | + | ||
| 27 | + | ||
| 28 | + # Else the element can only be present in right subarray | ||
| 29 | + | ||
| 30 | + else: | ||
| 31 | + | ||
| 32 | + return binary_search(arr, mid + 1, high, x) | ||
| 33 | + | ||
| 34 | + | ||
| 35 | + | ||
| 36 | + else: | ||
| 37 | + | ||
| 38 | + # Element is not present in the array | ||
| 39 | + | ||
| 40 | + return -1 | ||
| 41 | + | ||
| 42 | + | ||
| 43 | + | ||
| 44 | + arr = [ 2, 3, 4, 10, 40 ] | ||
| 45 | + | ||
| 46 | + x = 10 | ||
| 47 | + result = binary_search(arr, 0, len(arr)-1, x) | ||
| 48 | + if result != -1: | ||
| 49 | + | ||
| 50 | + print("Element is present at index", str(result)) | ||
| 51 | + | ||
| 52 | + else: | ||
| 53 | + | ||
| 54 | + print("Element is not present | ||
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