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Java/Dynamic Programming/Edit_Distance.java at master · ahern88/Java · GitHub
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/**
Author : SUBHAM SANGHAI
A Dynamic Programming based solution for Edit Distance problem In Java
**/
/**Description of Edit Distance with an Example:
Edit distance is a way of quantifying how dissimilar two strings (e.g., words) are to one another,
by counting the minimum number of operations required to transform one string into the other. The
distance operations are the removal, insertion, or substitution of a character in the string.
The Distance between "kitten" and "sitting" is 3. A minimal edit script that transforms the former into the latter is:
kitten → sitten (substitution of "s" for "k")
sitten → sittin (substitution of "i" for "e")
sittin → sitting (insertion of "g" at the end).**/
import
java
.
util
.
Scanner
;
public
class
Edit_Distance
{
public
static
int
minDistance
(
String
word1
,
String
word2
)
{
int
len1
=
word1
.
length
();
int
len2
=
word2
.
length
();
// len1+1, len2+1, because finally return dp[len1][len2]
int
[][]
dp
=
new
int
[
len1
+
1
][
len2
+
1
];
/* If second string is empty, the only option is to
insert all characters of first string into second*/
for
(
int
i
=
0
;
i
<=
len1
;
i
++)
{
dp
[
i
][
0
] =
i
;
}
/* If first string is empty, the only option is to
insert all characters of second string into first*/
for
(
int
j
=
0
;
j
<=
len2
;
j
++)
{
dp
[
0
][
j
] =
j
;
}
//iterate though, and check last char
for
(
int
i
=
0
;
i
<
len1
;
i
++)
{
char
c1
=
word1
.
charAt
(
i
);
for
(
int
j
=
0
;
j
<
len2
;
j
++)
{
char
c2
=
word2
.
charAt
(
j
);
//if last two chars equal
if
(
c1
==
c2
)
{
//update dp value for +1 length
dp
[
i
+
1
][
j
+
1
] =
dp
[
i
][
j
];
}
else
{
/* if two characters are different ,
then take the minimum of the various operations(i.e insertion,removal,substitution)*/
int
replace
=
dp
[
i
][
j
] +
1
;
int
insert
=
dp
[
i
][
j
+
1
] +
1
;
int
delete
=
dp
[
i
+
1
][
j
] +
1
;
int
min
=
replace
>
insert
?
insert
:
replace
;
min
=
delete
>
min
?
min
:
delete
;
dp
[
i
+
1
][
j
+
1
] =
min
;
}
}
}
/* return the final answer , after traversing through both the strings*/
return
dp
[
len1
][
len2
];
}
// Driver program to test above function
public
static
void
main
(
String
args
[])
{
Scanner
input
=
new
Scanner
(
System
.
in
);
String
s1
,
s2
;
System
.
out
.
println
(
"Enter the First String"
);
s1
=
input
.
nextLine
();
System
.
out
.
println
(
"Enter the Second String"
);
s2
=
input
.
nextLine
();
//ans stores the final Edit Distance between the two strings
int
ans
=
0
;
ans
=
minDistance
(
s1
,
s2
);
System
.
out
.
println
(
"The minimum Edit Distance between
\"
"
+
s1
+
"
\"
and
\"
"
+
s2
+
"
\"
is "
+
ans
);
}
}
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