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coding-Interview/KthSmallestElementBST.java at master · arjunmullick/coding-Interview · GitHub
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package
com
.
leetcode
;
import
java
.
util
.
LinkedList
;
import
java
.
util
.
List
;
//https://leetcode.com/problems/kth-smallest-element-in-a-bst/
public
class
KthSmallestElementBST
{
// No optimized , inorder till k nodes are added
class
Solution
{
public
int
kthSmallest
(
TreeNode
root
,
int
k
) {
List
<
TreeNode
>
arr
=
new
LinkedList
<>();
inorder
(
root
,
arr
,
k
);
return
arr
.
get
(
k
-
1
).
val
;
}
public
void
inorder
(
TreeNode
node
,
List
<
TreeNode
>
arr
,
int
k
){
if
(
arr
.
size
() ==
k
)
return
;
if
(
node
==
null
)
return
;
int
val
=
node
.
val
;
inorder
(
node
.
left
,
arr
,
k
);
arr
.
add
(
node
);
inorder
(
node
.
right
,
arr
,
k
);
}
}
//We dont need to store all values . Memory optimized.
class
Solution2
{
int
count
;
int
result
;
public
int
kthSmallest
(
TreeNode
root
,
int
k
) {
count
=
k
;
dfs
(
root
);
return
result
;
}
public
void
dfs
(
TreeNode
node
){
if
(
node
.
left
!=
null
)
dfs
(
node
.
left
);
count
--;
if
(
count
==
0
){
//it will only happen once that count = 0 can also add if(count == 0) return; as first condition
result
=
node
.
val
;
return
;
}
if
(
node
.
right
!=
null
)
dfs
(
node
.
right
);
}
}
public
class
TreeNode
{
int
val
;
TreeNode
left
;
TreeNode
right
;
TreeNode
() {}
TreeNode
(
int
val
) {
this
.
val
=
val
; }
TreeNode
(
int
val
,
TreeNode
left
,
TreeNode
right
) {
this
.
val
=
val
;
this
.
left
=
left
;
this
.
right
=
right
;
}
}
}
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