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leetcode-1/src/singleNumber/singleNumber.cpp at master · daction/leetcode-1 · GitHub
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singleNumber.cpp
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//
Source : https://oj.leetcode.com/problems/single-number/
//
Author : Hao Chen
//
Date : 2014-06-17
/*
*********************************************************************************
*
* Given an array of integers, every element appears twice except for one. Find that single one.
*
* Note:
* Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
*
*
*********************************************************************************
*/
#
include
<
stdio.h
>
//
This is classical interview question
//
As we know, the same number XOR together will be 0,
//
So, XOR all of numbers, the result is the number which only appears once.
int
singleNumber
(
int
A[],
int
n) {
int
s =
0
;
for
(
int
i=
0
; i<n; i++){
s = s^A[i];
}
return
s;
}
int
main
()
{
int
a[]={
1
,
1
,
2
,
2
,
3
};
printf
(
"
%d
\n
"
,
singleNumber
(a,
5
));
return
0
;
}
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