Given a year, determine whether it is a leap year. If it is a leap year, return the Boolean True, otherwise return False.

Note that the code stub provided reads from STDIN and passes arguments to the is_leap function. It is only necessary to complete the is_leap function.

Read year, the year to test.

1900 <= year <= 10^5

The function must return a Boolean value (True/False). Output is handled by the provided code stub.

1990

False

1990 is not a multiple of 4 hence it's not a leap year.

Solution Link : problem.py