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leetcode/code/lc572.java at master · mJackie/leetcode · GitHub
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lc572.java
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package
code
;
/*
* 572. Subtree of Another Tree
* 题意:判断一棵树是否为另外一棵树的子树
* 难度:Easy
* 分类:Tree
* 思路:两种方法,一种是先序遍历,然后比较字符串即可,注意每个节点开始前加个字符,null也要加进去。
* 另一种递归的方法。
* lc437 lc572 一样的递归思路
* lc297 序列化
* Tips:
*/
public
class
lc572
{
public
class
TreeNode
{
int
val
;
TreeNode
left
;
TreeNode
right
;
TreeNode
(
int
x
) {
val
=
x
; }
}
public
boolean
isSubtree
(
TreeNode
s
,
TreeNode
t
) {
if
(
s
==
null
||
t
==
null
)
return
s
==
t
;
return
helper
(
s
,
t
) ||
isSubtree
(
s
.
left
,
t
) ||
isSubtree
(
s
.
right
,
t
);
// 注意递归方法的不同,是调用哪个函数
}
public
boolean
helper
(
TreeNode
s
,
TreeNode
t
){
if
(
s
==
null
||
t
==
null
)
return
s
==
t
;
return
s
.
val
==
t
.
val
&&
helper
(
s
.
left
,
t
.
left
) &&
helper
(
s
.
right
,
t
.
right
);
}
public
boolean
isSubtree2
(
TreeNode
s
,
TreeNode
t
) {
StringBuilder
tree1
=
new
StringBuilder
();
StringBuilder
tree2
=
new
StringBuilder
();
helper2
(
s
,
tree1
);
helper2
(
s
,
tree2
);
return
tree1
.
toString
().
contains
(
tree2
.
toString
());
}
public
void
helper2
(
TreeNode
node
,
StringBuilder
res
){
if
(
node
==
null
)
res
.
append
(
",#"
);
//先放','表示一个新节点的开始,#代表null
else
{
res
.
append
(
","
+
node
.
val
);
helper2
(
node
.
left
,
res
);
helper2
(
node
.
right
,
res
);
}
}
}
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