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pythonCollection/dailyCodingTask/steppingNumbers.py at master · marcelpetrick/pythonCollection · GitHub
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dailyCodingTask
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steppingNumbers.py
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dailyCodingTask
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steppingNumbers.py
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# Stepping Numbers
# Given two integers ‘n’ and ‘m’, find all the stepping numbers in range [n, m].
# A number is called stepping number if all adjacent digits have an absolute difference of 1.
# 321 is a Stepping Number while 421 is not.
#
# Examples :
# Input : n = 0, m = 21
# Output : 0 1 2 3 4 5 6 7 8 9 10 12 21
#
# Input : n = 10, m = 15
# Output : 10, 12
# ------------------------------------------------------------------------------
def
printSteppingNumbersInRange
(
m
,
n
):
'''
@param: m begin (inclusive)
@param: n end (inclusive)
'''
results
=
[]
for
number
in
range
(
m
,
n
+
1
):
# n should be inclusive, therefore +1
if
isSteppingNumber
(
number
):
results
.
append
(
number
)
return
results
# ------------------------------------------------------------------------------
def
isSteppingNumber
(
number
):
numberOfDigits
=
str
(
number
).
__len__
()
if
(
numberOfDigits
==
1
):
returnValue
=
True
else
:
current
=
0
next
=
number
%
10
number
//=
10
returnValue
=
True
for
position
in
range
(
0
,
numberOfDigits
-
1
):
# use div and mod to acquire the digits and check them
current
=
next
next
=
number
%
10
if
(
abs
(
next
-
current
)
!=
1
):
#print("current and next differ by more than one:", current, next)
returnValue
=
False
break
number
//=
10
#print("isSteppingNumber:", originalNumber, "returns", returnValue)
#print("###################")
return
returnValue
# ------------------------------------------------------------------------------
print
(
"-----------------------------------------------------------------------------"
)
print
(
"range(10,15):"
,
printSteppingNumbersInRange
(
10
,
15
))
print
(
"range(0,100):"
,
printSteppingNumbersInRange
(
0
,
100
))
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