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pygorithm/pygorithm/binary/base2.py at master · mikechen66/pygorithm · GitHub
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base2.py
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binary
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base2.py
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"""
Binary: Base2
Conversions from base2 to:
- base10
- base16
- ASCII
Author: Ian Doarn
"""
BINARY_HEX_VALUES
=
{
"0000"
:
"0"
,
"0001"
:
"1"
,
"0010"
:
"2"
,
"0011"
:
"3"
,
"0100"
:
"4"
,
"0101"
:
"5"
,
"0110"
:
"6"
,
"0111"
:
"7"
,
"1000"
:
"8"
,
"1001"
:
"9"
,
"1010"
:
"A"
,
"1011"
:
"B"
,
"1100"
:
"C"
,
"1101"
:
"D"
,
"1110"
:
"E"
,
"1111"
:
"F"
}
def
to_ascii
(
b
,
visualize
=
False
):
"""
Convert binary to ASCII
:param b: binary number or array
:param visualize: Show process
:return: ASCII String
"""
binary
=
b
# Make sure give binary is a str array
if
type
(
b
)
is
str
:
binary
=
b
.
split
(
' '
)
elif
type
(
b
)
is
list
:
binary
=
b
string
=
''
for
b_value
in
binary
:
if
visualize
:
print
(
"{} -> {} -> {}"
.
format
(
b_value
,
to_base10
(
int
(
b_value
)),
chr
(
to_base10
(
int
(
b_value
)))
))
value
=
to_base10
(
int
(
b_value
))
string
+=
chr
(
value
)
return
string
def
to_base10
(
n
,
visualize
=
False
):
"""
Convert given number to a list
for every number do the following formula
x * 2 + number
repeat for each result! Example:
binary number = 100110
0 x 2 + 1 = 1
1 x 2 + 0 = 2
2 x 2 + 0 = 4
4 x 2 + 1 = 9
9 x 2 + 1 = 19
19 x 2 + 0 = 38
:param n: binary number
:param visualize: Show process
:return: decimal number
"""
if
type
(
n
)
is
str
:
raise
ValueError
(
'value must be int not type {}'
.
format
(
str
(
type
(
n
))))
x
=
0
_list
=
[
int
(
i
)
for
i
in
str
(
n
)]
for
number
in
_list
:
if
visualize
:
print
(
"{} x 2 + {} = {}"
.
format
(
str
(
x
),
str
(
number
),
str
(
x
*
2
+
number
)))
x
=
x
*
2
+
number
return
x
def
to_base16
(
n
,
visualize
=
False
):
"""
Convert binary numbers to hexadecimal numbers
:param n: binary number
:param visualize: Visualise the process
:return: hexadecimal number
"""
grouped_list
=
__create_group_list
(
n
)
_list
=
[]
for
value
in
grouped_list
:
if
visualize
:
print
(
"{} -> {}"
.
format
(
value
,
BINARY_HEX_VALUES
[
value
]))
# for each value in the grouped_list,
# get its respective value from the hex
# table by referencing the key with the
# current value from the grouped_list
_list
.
append
(
BINARY_HEX_VALUES
[
value
])
return
''
.
join
(
_list
)
def
__create_group_list
(
n
):
"""
Helper method for conversion
Takes binary number and converts to a list of
grouped binary values
Process:
1. convert number to a list of chars
2. reverse the list
3. iterate through the list creating groups of 4
removing each value as its iterated
4. if the remaining values can not make a group,
add 0's to the end to get to 4
5. join each list together
6. reverse each value in the final list to put
them back in order
Example:
n = 11101100101001001100101001
reverse = 10010100110010010100110111
Start grouping values:
[['1', '0', '0', '1'],
['0', '1', '0', '0'],
['1', '1', '0', '0'],
['1', '0', '0', '1'],
['0', '1', '0', '0'],
['1', '1', '0', '1']]
remaining value = 11
add missing 0's -> 1100
join each list:
['1', '0', '0', '1'] = 1001
['0', '1', '0', '0'] = 0100
['1', '1', '0', '0'] = 1100
['1', '0', '0', '1'] = 1001
['0', '1', '0', '0'] = 0100
['1', '1', '0', '1'] = 1101
['1100', '1101', '0100', '1001', '1100', '0100', '1001']
reverse final list
result = ['0011', '1011', '0010', '1001', '0011', '0010', '1001']
:param n: binary number
:return: list
"""
reversed_number_list
=
list
(
str
(
n
)[::
-
1
])
grouped_list
=
[]
while
len
(
reversed_number_list
)
!=
0
:
# go until list is empty
if
len
(
reversed_number_list
)
<
4
:
# remaining values can not make a group
# join remaining values
value
=
''
.
join
(
reversed_number_list
)
# find the missing amount needed then add that many
# zeros to the end of the value
f_value
=
value
+
(
'0'
*
(
4
-
len
(
value
)))
# add to the group
grouped_list
.
append
(
f_value
)
break
else
:
temp_list
=
[]
while
len
(
temp_list
)
!=
4
:
# go until temp list does not have 4 values
temp_list
.
append
(
reversed_number_list
.
pop
(
0
))
# join each value in temp list and add to group
grouped_list
.
append
(
''
.
join
(
temp_list
))
# reverse the entire grouped_list
# then reverse each value in the grouped_list
# and return the results
return
[
i
[::
-
1
]
for
i
in
grouped_list
[::
-
1
]]
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