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leetcode/src/combinations/combinations.cpp at master · ourstart/leetcode · GitHub
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//
Source : https://oj.leetcode.com/problems/combinations/
//
Author : Hao Chen
//
Date : 2014-07-03
/*
*********************************************************************************
*
* Given two integers n and k, return all possible combinations of k numbers out of 1 ... n.
*
* For example,
* If n = 4 and k = 2, a solution is:
*
* [
* [2,4],
* [3,4],
* [2,3],
* [1,2],
* [1,3],
* [1,4],
* ]
*
*
*********************************************************************************
*/
#
include
<
stdio.h
>
#
include
<
stdlib.h
>
#
include
<
time.h
>
#
include
<
iostream
>
#
include
<
vector
>
#
include
<
algorithm
>
using
namespace
std
;
void
getCombination
(
int
n,
int
k, vector<
int
>& solution, vector< vector<
int
> >& result );
vector<vector<
int
> >
combine1
(
int
n,
int
k);
vector<vector<
int
> >
combine2
(
int
n,
int
k);
vector<vector<
int
> >
combine
(
int
n,
int
k) {
if
(
random
()%
2
){
cout <<
"
recusive method!
"
<< endl;
return
combine1
(n, k);
}
cout <<
"
non-recusive method!
"
<< endl;
return
combine2
(n, k);
}
vector<vector<
int
> >
combine1
(
int
n,
int
k) {
vector<vector<
int
> > result;
vector<
int
> solution;
getCombination
(n, k, solution, result);
return
result;
}
void
getCombination
(
int
n,
int
k, vector<
int
>& solution, vector< vector<
int
> >& result ){
if
(k==
0
){
//
sort to meet LeetCode requirement
vector<
int
> v = solution;
sort
(v.
begin
(), v.
end
());
result.
push_back
(v);
return
;
}
for
(
int
i=n; i>
0
; i--){
solution.
push_back
(i);
getCombination
(i-
1
, k-
1
, solution, result);
solution.
pop_back
();
}
}
vector<vector<
int
> >
combine2
(
int
n,
int
k) {
vector<vector<
int
> > result;
vector<
int
> d;
for
(
int
i=
0
; i<n; i++){
d.
push_back
( (i<k) ?
1
:
0
);
}
//
1) from the left, find the [1,0] pattern, change it to [0,1]
//
2) move all of the 1 before the pattern to the most left side
//
3) check all of 1 move to the right
while
(
1
){
vector<
int
> v;
for
(
int
x=
0
; x<n; x++){
if
(d[x]) v.
push_back
(x+
1
);
}
result.
push_back
(v);
//
step 1), find [1,0] pattern
int
i;
bool
found =
false
;
int
ones =
0
;
for
(i=
0
; i<n-
1
; i++){
if
(d[i]==
1
&& d[i+
1
]==
0
){
d[i]=
0
; d[i+
1
]=
1
;
found =
true
;
//
step 2) move all of right 1 to the most left side
for
(
int
j=
0
; j<i; j++){
d[j]=( ones >
0
) ?
1
:
0
;
ones--;
}
break
;
}
if
(d[i]==
1
) ones++;
}
if
(!found){
break
;
}
}
return
result;
}
void
printResult
(vector<vector<
int
> >& result)
{
for
(
int
i=
0
; i<result.
size
(); i++){
cout <<
"
{
"
;
for
(
int
j=
0
; j<result[i].
size
(); j++){
cout <<
"
"
<< result[i][j];
}
cout <<
"
}
"
<<endl;
}
}
int
main
(
int
argc,
char
** argv)
{
srand
(
time
(
NULL
));
int
n =
4
, k =
2
;
if
(argc>
2
){
n =
atoi
(argv[
1
]);
k =
atoi
(argv[
2
]);
}
vector<vector<
int
> > r =
combine
(n, k);
printResult
(r);
}
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