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LeetCode-Solutions/Python/basic-calculator-ii.py at master · pythonpeixun/LeetCode-Solutions · GitHub
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basic-calculator-ii.py
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LeetCode-Solutions
/
Python
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basic-calculator-ii.py
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# Time: O(n)
# Space: O(n)
class
Solution
(
object
):
# @param {string} s
# @return {integer}
def
calculate
(
self
,
s
):
operands
,
operators
=
[], []
operand
=
""
for
i
in
reversed
(
xrange
(
len
(
s
))):
if
s
[
i
].
isdigit
():
operand
+=
s
[
i
]
if
i
==
0
or
not
s
[
i
-
1
].
isdigit
():
operands
.
append
(
int
(
operand
[::
-
1
]))
operand
=
""
elif
s
[
i
]
==
')'
or
s
[
i
]
==
'*'
or
s
[
i
]
==
'/'
:
operators
.
append
(
s
[
i
])
elif
s
[
i
]
==
'+'
or
s
[
i
]
==
'-'
:
while
operators
and
\
(
operators
[
-
1
]
==
'*'
or
operators
[
-
1
]
==
'/'
):
self
.
compute
(
operands
,
operators
)
operators
.
append
(
s
[
i
])
elif
s
[
i
]
==
'('
:
while
operators
[
-
1
]
!=
')'
:
self
.
compute
(
operands
,
operators
)
operators
.
pop
()
while
operators
:
self
.
compute
(
operands
,
operators
)
return
operands
[
-
1
]
def
compute
(
self
,
operands
,
operators
):
left
,
right
=
operands
.
pop
(),
operands
.
pop
()
op
=
operators
.
pop
()
if
op
==
'+'
:
operands
.
append
(
left
+
right
)
elif
op
==
'-'
:
operands
.
append
(
left
-
right
)
elif
op
==
'*'
:
operands
.
append
(
left
*
right
)
elif
op
==
'/'
:
operands
.
append
(
left
/
right
)
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