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LeetCode-Solutions/Python/permutations.py at master · pythonpeixun/LeetCode-Solutions · GitHub
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LeetCode-Solutions
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Python
/
permutations.py
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53 lines (47 loc) · 1.57 KB
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LeetCode-Solutions
/
Python
/
permutations.py
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# Time: O(n * n!)
# Space: O(n)
class
Solution
(
object
):
# @param num, a list of integer
# @return a list of lists of integers
def
permute
(
self
,
num
):
result
=
[]
used
=
[
False
]
*
len
(
num
)
self
.
permuteRecu
(
result
,
used
, [],
num
)
return
result
def
permuteRecu
(
self
,
result
,
used
,
cur
,
num
):
if
len
(
cur
)
==
len
(
num
):
result
.
append
(
cur
[:])
return
for
i
in
xrange
(
len
(
num
)):
if
not
used
[
i
]:
used
[
i
]
=
True
cur
.
append
(
num
[
i
])
self
.
permuteRecu
(
result
,
used
,
cur
,
num
)
cur
.
pop
()
used
[
i
]
=
False
# Time: O(n^2 * n!)
# Space: O(n^2)
class
Solution2
(
object
):
def
permute
(
self
,
nums
):
"""
:type nums: List[int]
:rtype: List[List[int]]
"""
res
=
[]
self
.
dfs
(
nums
, [],
res
)
return
res
def
dfs
(
self
,
nums
,
path
,
res
):
if
not
nums
:
res
.
append
(
path
)
for
i
in
xrange
(
len
(
nums
)):
# e.g., [1, 2, 3]: 3! = 6 cases
# idx -> nums, path
# 0 -> [2, 3], [1] -> 0: [3], [1, 2] -> [], [1, 2, 3]
# -> 1: [2], [1, 3] -> [], [1, 3, 2]
#
# 1 -> [1, 3], [2] -> 0: [3], [2, 1] -> [], [2, 1, 3]
# -> 1: [1], [2, 3] -> [], [2, 3, 1]
#
# 2 -> [1, 2], [3] -> 0: [2], [3, 1] -> [], [3, 1, 2]
# -> 1: [1], [3, 2] -> [], [3, 2, 1]
self
.
dfs
(
nums
[:
i
]
+
nums
[
i
+
1
:],
path
+
[
nums
[
i
]],
res
)
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