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LeetCode-Solutions/Python/minimum-size-subarray-sum.py at master · tehsints/LeetCode-Solutions · GitHub
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LeetCode-Solutions
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Python
/
minimum-size-subarray-sum.py
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50 lines (44 loc) · 1.53 KB
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LeetCode-Solutions
/
Python
/
minimum-size-subarray-sum.py
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# Time: O(n)
# Space: O(1)
class
Solution
(
object
):
# @param {integer} s
# @param {integer[]} nums
# @return {integer}
def
minSubArrayLen
(
self
,
s
,
nums
):
start
=
0
sum
=
0
min_size
=
float
(
"inf"
)
for
i
in
xrange
(
len
(
nums
)):
sum
+=
nums
[
i
]
while
sum
>=
s
:
min_size
=
min
(
min_size
,
i
-
start
+
1
)
sum
-=
nums
[
start
]
start
+=
1
return
min_size
if
min_size
!=
float
(
"inf"
)
else
0
# Time: O(nlogn)
# Space: O(n)
# Binary search solution.
class
Solution2
(
object
):
# @param {integer} s
# @param {integer[]} nums
# @return {integer}
def
minSubArrayLen
(
self
,
s
,
nums
):
min_size
=
float
(
"inf"
)
sum_from_start
=
[
n
for
n
in
nums
]
for
i
in
xrange
(
len
(
sum_from_start
)
-
1
):
sum_from_start
[
i
+
1
]
+=
sum_from_start
[
i
]
for
i
in
xrange
(
len
(
sum_from_start
)):
end
=
self
.
binarySearch
(
lambda
x
,
y
:
x
<=
y
,
sum_from_start
, \
i
,
len
(
sum_from_start
), \
sum_from_start
[
i
]
-
nums
[
i
]
+
s
)
if
end
<
len
(
sum_from_start
):
min_size
=
min
(
min_size
,
end
-
i
+
1
)
return
min_size
if
min_size
!=
float
(
"inf"
)
else
0
def
binarySearch
(
self
,
compare
,
A
,
start
,
end
,
target
):
while
start
<
end
:
mid
=
start
+
(
end
-
start
)
/
2
if
compare
(
target
,
A
[
mid
]):
end
=
mid
else
:
start
=
mid
+
1
return
start
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