std::filesystem::path::compare

`int compare( const path& p ) const noexcept;`	(1)	(C++17)
`int compare( const string_type& str ) const; int compare( std::basic_string_view<value_type> str ) const;`	(2)	(C++17)
`int compare( const value_type* s ) const;`	(3)	(C++17)

1) root_name().native().compare(p.root_name().native())

has_root_directory() != p.has_root_directory() has_root_directory() false

(relative_path()) p (p.relative_path())

0

begin() end() native()

2) compare(path(str))

3) compare(path(s))

p	-
str	-
s	-

$0$

2-3) ()

Run this code

#include <iostream>
#include <filesystem>
namespace fs = std::filesystem;
void demo(int rc, fs::path p1, fs::path p2) {
    if(rc < 0) std::cout << p1 << " < " << p2 << '\n';
    else if(rc > 0) std::cout << p1 << " > "  << p2 << '\n';
    else if(rc == 0) std::cout << p1 << "==" << p2 << '\n';
}
int main() {
    fs::path p1 = "/a/b/"; // as if "a/b/." for lexicographical iteration
    fs::path p2 = "/a/b/#";
    demo(p1.compare(p2), p1, p2);
    demo(p1.compare("a/b/_"), p1, "a/b/_");
}

:

"/a/b/" > "/a/b/#"
"/a/b/" < "a/b/_"

C++

DR
LWG 2936	C++17	compared all path elements directly	root name and root directory handled separately

operator==operator!=operator<operator<=operator>operator>=operator<=>

(C++20)(C++20)(C++20)(C++20)(C++20)(C++20)

2
() [edit]






(C++20)





(C++20)




(C++17)
(C++11)
(C++11)
(C++11)

cppreference.com

std::filesystem::path::compare