FazBrowse GitHub Viewer | Trending |
URL:
| Home
Tools: [Download Repo ZIP]   [Original HTTPS Page]

Refactored the code to reduce time complexity by SwayamSahu · Pull Request #148 · AllAlgorithms/python · GitHub

This repository was archived by the owner on Sep 7, 2025. It is now read-only.
/ python Public archive

Refactored the code to reduce time complexity #148

Open
SwayamSahu wants to merge 1 commit into
base: master
Choose a base branch
Could not load branches
Branch not found: {{ refName }}

Are you sure you want to change the base?

Some commits from the old base branch may be removed from the timeline, and old review comments may become outdated.
from
Conversation 0 Commits 1 Checks 0 Files changed
Open

Refactored the code to reduce time complexity #148

Changes from all commits
Commits
Show all changes
1 commit
Select commit
File filter

Filter by extension

Filter by extension .py  (1) All 1 file type selected
Viewed files
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Unified
Split
Hide whitespace
Diff view
Unified
Split
Hide whitespace
31 changes: 17 additions & 14 deletions algorithms/strings/anagram_check.py
Show comments
View file
Open in desktop
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters. Learn more about bidirectional Unicode characters
Show hidden characters
Original file line number Diff line number Diff line change
@@ -1,14 +1,17 @@
# function to check if two strings are
# anagram or not
def check(s1, s2):

# the sorted strings are checked
if(sorted(s1)== sorted(s2)):
print("The strings are anagrams.")
else:
print("The strings aren't anagrams.")

# driver code
s1 ="listen" #String 1
s2 ="silent" #String 2
check(s1, s2)
from collections import Counter

# function to check if two strings are
# anagram or not
def check(s1, s2):

# implementing counter function
if(Counter(s1) == Counter(s2)):
print("The strings are anagrams.")
else:
print("The strings aren't anagrams.")


# driver code
s1 = "listen"
s2 = "silent"
check(s1, s2)
Back | FazBrowse Home | New Git URL