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A mutable, self-balancing interval tree for Python 2 and 3. Queries may be by point, by range overlap, or by range envelopment.
This library was designed to allow tagging text and time intervals, where the intervals include the lower bound but not the upper bound.
This means that 0-length intervals are null and overlap nothing. If you see errors about null intervals, make sure end is strictly greater than begin. Our Intervals are like string ranges: 'hello'[0:0] == '', but 'hello'[0:1] == 'h'.
Version 3 changes!
pip install intervaltreeSupports Python 2.7 and Python 3.5+ (Tested under 2.7, and 3.5 thru 3.14)
Initializing
Insertions
Deletions
Point queries
Overlap queries
Envelop queries
Membership queries
Iterable
Sizing
Set-like operations
union
difference
intersection
symmetric difference
comparison
Restructuring
Copying and typecasting
Pickle-friendly
Automatic AVL balancing
Getting started
>>> from intervaltree import Interval, IntervalTree
>>> t = IntervalTree()
>>> t
IntervalTree()Adding intervals - any object works!
>>> t[1:2] = "1-2"
>>> t[4:7] = (4, 7)
>>> t[5:9] = {5: 9}Query by point
The result of a query is a set object, so if ordering is important, you must sort it first.
>>> sorted(t[6])
[Interval(4, 7, (4, 7)), Interval(5, 9, {5: 9})]
>>> sorted(t[6])[0]
Interval(4, 7, (4, 7))Query by range
Note that ranges are inclusive of the lower limit, but non-inclusive of the upper limit. So:
>>> sorted(t[2:4])
[]Since our search was over 2 ≤ x < 4, neither Interval(1, 2) nor Interval(4, 7) was included. The first interval, 1 ≤ x < 2 does not include x = 2. The second interval, 4 ≤ x < 7, does include x = 4, but our search interval excludes it. So, there were no overlapping intervals. However:
>>> sorted(t[1:5])
[Interval(1, 2, '1-2'), Interval(4, 7, (4, 7))]To only return intervals that are completely enveloped by the search range:
>>> sorted(t.envelop(1, 5))
[Interval(1, 2, '1-2')]Accessing an Interval object
>>> iv = Interval(4, 7, (4, 7))
>>> iv.begin
4
>>> iv.end
7
>>> iv.data
(4, 7)
>>> begin, end, data = iv
>>> begin
4
>>> end
7
>>> data
(4, 7)Constructing from lists of intervals
We could have made a similar tree this way:
>>> ivs = [(1, 2), (4, 7), (5, 9)]
>>> t = IntervalTree(
... Interval(begin, end, "%d-%d" % (begin, end)) for begin, end in ivs
... )Or, if we don't need the data fields:
>>> t2 = IntervalTree(Interval(*iv) for iv in ivs)Or even:
>>> t2 = IntervalTree.from_tuples(ivs)Removing intervals
>>> t.remove(Interval(1, 2, "1-2"))
>>> sorted(t)
[Interval(4, 7, '4-7'), Interval(5, 9, '5-9')]
>>> t.remove(Interval(500, 1000, "Doesn't exist")) # raises ValueError
Traceback (most recent call last):
ValueError
>>> t.discard(Interval(500, 1000, "Doesn't exist")) # quietly does nothing
>>> del t[5] # same as t.remove_overlap(5)
>>> t
IntervalTree()We could also empty a tree entirely:
>>> t2.clear()
>>> t2
IntervalTree()Or remove intervals that overlap a range:
>>> t = IntervalTree([
... Interval(0, 10),
... Interval(10, 20),
... Interval(20, 30),
... Interval(30, 40)])
>>> t.remove_overlap(25, 35)
>>> sorted(t)
[Interval(0, 10), Interval(10, 20)]We can also remove only those intervals completely enveloped in a range:
>>> t.remove_envelop(5, 20)
>>> sorted(t)
[Interval(0, 10)]Chopping
We could also chop out parts of the tree:
>>> t = IntervalTree([Interval(0, 10)])
>>> t.chop(3, 7)
>>> sorted(t)
[Interval(0, 3), Interval(7, 10)]To modify the new intervals' data fields based on which side of the interval is being chopped:
>>> def datafunc(iv, islower):
... oldlimit = iv[islower]
... return "oldlimit: {0}, islower: {1}".format(oldlimit, islower)
>>> t = IntervalTree([Interval(0, 10)])
>>> t.chop(3, 7, datafunc)
>>> sorted(t)[0]
Interval(0, 3, 'oldlimit: 10, islower: True')
>>> sorted(t)[1]
Interval(7, 10, 'oldlimit: 0, islower: False')Slicing
You can also slice intervals in the tree without removing them:
>>> t = IntervalTree([Interval(0, 10), Interval(5, 15)])
>>> t.slice(3)
>>> sorted(t)
[Interval(0, 3), Interval(3, 10), Interval(5, 15)]You can also set the data fields, for example, re-using datafunc() from above:
>>> t = IntervalTree([Interval(5, 15)])
>>> t.slice(10, datafunc)
>>> sorted(t)[0]
Interval(5, 10, 'oldlimit: 15, islower: True')
>>> sorted(t)[1]
Interval(10, 15, 'oldlimit: 5, islower: False')See the issue tracker on GitHub.
Licensed under the Apache License, version 2.0.
The source code for this project is at https://github.com/chaimleib/intervaltree
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