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Manhole is in-process service that will accept unix domain socket connections and present the stacktraces for all threads and an interactive prompt. It can either work as a python daemon thread waiting for connections at all times or a signal handler (stopping your application and waiting for a connection).
Access to the socket is restricted to the application's effective user id or root.
This is just like Twisted's manhole. It's simpler (no dependencies), it only runs on Unix domain sockets (in contrast to Twisted's manhole which can run on telnet or ssh) and it integrates well with various types of applications.
| Documentation: | http://python-manhole.readthedocs.org/en/latest/ |
|---|
Install it:
pip install manhole
You can put this in your django settings, wsgi app file, some module that's always imported early etc:
import manhole
manhole.install() # this will start the daemon thread
# and now you start your app, eg: server.serve_forever()Now in a shell you can do either of these:
netcat -U /tmp/manhole-1234 socat - unix-connect:/tmp/manhole-1234 socat readline unix-connect:/tmp/manhole-1234
Socat with readline is best (history, editing etc). If your socat doesn't have readline try this.
Sample output:
$ nc -U /tmp/manhole-1234 Python 2.7.3 (default, Apr 10 2013, 06:20:15) [GCC 4.6.3] on linux2 Type "help", "copyright", "credits" or "license" for more information. (InteractiveConsole) >>> dir() ['__builtins__', 'dump_stacktraces', 'os', 'socket', 'sys', 'traceback'] >>> print 'foobar' foobar
There's a new experimental manhole-cli bin since 1.1.0, that emulates socat:
usage: manhole-cli [-h] [-t TIMEOUT] [-1 | -2 | -s SIGNAL] PID
Connect to a manhole.
positional arguments:
PID A numerical process id, or a path in the form:
/tmp/manhole-1234
optional arguments:
-h, --help show this help message and exit
-t TIMEOUT, --timeout TIMEOUT
Timeout to use. Default: 1 seconds.
-1, -USR1 Send USR1 (10) to the process before connecting.
-2, -USR2 Send USR2 (12) to the process before connecting.
-s SIGNAL, --signal SIGNAL
Send the given SIGNAL to the process before
connecting.
Uses unix domain sockets, only root or same effective user can connect.
Can run the connection in a thread or in a signal handler (see oneshot_on option).
Can start the thread listening for connections from a signal handler (see activate_on option)
Compatible with apps that fork, reinstalls the Manhole thread after fork - had to monkeypatch os.fork/os.forkpty for this.
Compatible with gevent and eventlet with some limitations - you need to either:
Note: on eventlet you might need to setup the hub first to prevent circular import problems:
import eventlet
eventlet.hubs.get_hub() # do this first
eventlet.monkey_patch(thread=False)The thread is compatible with apps that use signalfd (will mask all signals for the Manhole threads).
manhole.install(
verbose=True,
verbose_destination=2,
patch_fork=True,
activate_on=None,
oneshot_on=None,
sigmask=manhole.ALL_SIGNALS,
socket_path=None,
reinstall_delay=0.5,
locals=None,
strict=True,
)Manhole can be installed via the PYTHONMANHOLE environment variable.
This:
PYTHONMANHOLE='' python yourapp.py
Is equivalent to having this in yourapp.py:
import manhole manhole.install()
Any extra text in the environment variable is passed to manhole.install(). Example:
PYTHONMANHOLE='oneshot_on="USR2"' python yourapp.py
By default Python doesn't call the atexit callbacks with the default SIGTERM handling. This makes manhole leave stray socket files around. If this is undesirable you should install a custom SIGTERM handler so atexit is properly invoked.
Example:
import signal
import sys
def handle_sigterm(signo, frame):
sys.exit(128 + signo) # this will raise SystemExit and cause atexit to be called
signal.signal(signal.SIGTERM, handle_sigterm)Because uWSGI overrides signal handling Manhole is a bit more tricky to setup. One way is to use "uWSGI signals" (not the POSIX signals) and have the workers check a file for the pid you want to open the Manhole in.
Stick something this in your WSGI application file:
from __future__ import print_function
import sys
import os
import manhole
stack_dump_file = '/tmp/manhole-pid'
uwsgi_signal_number = 17
try:
import uwsgi
if not os.path.exists(stack_dump_file):
open(stack_dump_file, 'w')
def open_manhole(dummy_signum):
with open(stack_dump_file, 'r') as fh:
pid = fh.read().strip()
if pid == str(os.getpid()):
inst = manhole.install(strict=False, thread=False)
inst.handle_oneshot(dummy_signum, dummy_signum)
uwsgi.register_signal(uwsgi_signal_number, 'workers', open_manhole)
uwsgi.add_file_monitor(uwsgi_signal_number, stack_dump_file)
print("Listening for stack mahole requests via %r" % (stack_dump_file,), file=sys.stderr)
except ImportError:
print("Not running under uwsgi; unable to configure manhole trigger", file=sys.stderr)
except IOError:
print("IOError creating manhole trigger %r" % (stack_dump_file,), file=sys.stderr)
# somewhere bellow you'd have something like
from django.core.wsgi import get_wsgi_application
application = get_wsgi_application()
# or
def application(environ, start_response):
start_response('200 OK', [('Content-Type', 'text/plain'), ('Content-Length', '2')])
yield b'OK'To open the Manhole just run echo 1234 > /tmp/manhole-pid and then manhole-cli 1234.
| OS: | Linux, OS X |
|---|---|
| Runtime: | Python 2.7, 3.4, 3.5, 3.6 or PyPy |
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