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[3.12] gh-124130: Increase test coverage for \b and \B in regular expressions (GH-124330) by miss-islington · Pull Request #124414 · python/cpython · GitHub

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120 changes: 113 additions & 7 deletions Lib/test/test_re.py
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters. Learn more about bidirectional Unicode characters
Original file line number Diff line number Diff line change
Expand Up @@ -820,31 +820,137 @@ def test_named_unicode_escapes(self):
self.checkPatternError(br'\N{LESS-THAN SIGN}', r'bad escape \N', 0)
self.checkPatternError(br'[\N{LESS-THAN SIGN}]', r'bad escape \N', 1)

def test_string_boundaries(self):
def test_word_boundaries(self):
# See http://bugs.python.org/issue10713
self.assertEqual(re.search(r"\b(abc)\b", "abc").group(1),
"abc")
self.assertEqual(re.search(r"\b(abc)\b", "abc").group(1), "abc")
self.assertEqual(re.search(r"\b(abc)\b", "abc", re.ASCII).group(1), "abc")
self.assertEqual(re.search(br"\b(abc)\b", b"abc").group(1), b"abc")
self.assertEqual(re.search(br"\b(abc)\b", b"abc", re.LOCALE).group(1), b"abc")
self.assertEqual(re.search(r"\b(ьюя)\b", "ьюя").group(1), "ьюя")
self.assertIsNone(re.search(r"\b(ьюя)\b", "ьюя", re.ASCII))
# There's a word boundary between a word and a non-word.
self.assertTrue(re.match(r".\b", "a="))
self.assertTrue(re.match(r".\b", "a=", re.ASCII))
self.assertTrue(re.match(br".\b", b"a="))
self.assertTrue(re.match(br".\b", b"a=", re.LOCALE))
self.assertTrue(re.match(r".\b", "я="))
self.assertIsNone(re.match(r".\b", "я=", re.ASCII))
# There's a word boundary between a non-word and a word.
self.assertTrue(re.match(r".\b", "=a"))
self.assertTrue(re.match(r".\b", "=a", re.ASCII))
self.assertTrue(re.match(br".\b", b"=a"))
self.assertTrue(re.match(br".\b", b"=a", re.LOCALE))
self.assertTrue(re.match(r".\b", "=я"))
self.assertIsNone(re.match(r".\b", "=я", re.ASCII))
# There is no word boundary inside a word.
self.assertIsNone(re.match(r".\b", "ab"))
self.assertIsNone(re.match(r".\b", "ab", re.ASCII))
self.assertIsNone(re.match(br".\b", b"ab"))
self.assertIsNone(re.match(br".\b", b"ab", re.LOCALE))
self.assertIsNone(re.match(r".\b", "юя"))
self.assertIsNone(re.match(r".\b", "юя", re.ASCII))
# There is no word boundary between a non-word characters.
self.assertIsNone(re.match(r".\b", "=-"))
self.assertIsNone(re.match(r".\b", "=-", re.ASCII))
self.assertIsNone(re.match(br".\b", b"=-"))
self.assertIsNone(re.match(br".\b", b"=-", re.LOCALE))
# There is no non-boundary match between a word and a non-word.
self.assertIsNone(re.match(r".\B", "a="))
self.assertIsNone(re.match(r".\B", "a=", re.ASCII))
self.assertIsNone(re.match(br".\B", b"a="))
self.assertIsNone(re.match(br".\B", b"a=", re.LOCALE))
self.assertIsNone(re.match(r".\B", "я="))
self.assertTrue(re.match(r".\B", "я=", re.ASCII))
# There is no non-boundary match between a non-word and a word.
self.assertIsNone(re.match(r".\B", "=a"))
self.assertIsNone(re.match(r".\B", "=a", re.ASCII))
self.assertIsNone(re.match(br".\B", b"=a"))
self.assertIsNone(re.match(br".\B", b"=a", re.LOCALE))
self.assertIsNone(re.match(r".\B", "=я"))
self.assertTrue(re.match(r".\B", "=я", re.ASCII))
# There's a non-boundary match inside a word.
self.assertTrue(re.match(r".\B", "ab"))
self.assertTrue(re.match(r".\B", "ab", re.ASCII))
self.assertTrue(re.match(br".\B", b"ab"))
self.assertTrue(re.match(br".\B", b"ab", re.LOCALE))
self.assertTrue(re.match(r".\B", "юя"))
self.assertTrue(re.match(r".\B", "юя", re.ASCII))
# There's a non-boundary match between a non-word characters.
self.assertTrue(re.match(r".\B", "=-"))
self.assertTrue(re.match(r".\B", "=-", re.ASCII))
self.assertTrue(re.match(br".\B", b"=-"))
self.assertTrue(re.match(br".\B", b"=-", re.LOCALE))
# There's a word boundary at the start of a string.
self.assertTrue(re.match(r"\b", "abc"))
self.assertTrue(re.match(r"\b", "abc", re.ASCII))
self.assertTrue(re.match(br"\b", b"abc"))
self.assertTrue(re.match(br"\b", b"abc", re.LOCALE))
self.assertTrue(re.match(r"\b", "ьюя"))
self.assertIsNone(re.match(r"\b", "ьюя", re.ASCII))
# There's a word boundary at the end of a string.
self.assertTrue(re.fullmatch(r".+\b", "abc"))
self.assertTrue(re.fullmatch(r".+\b", "abc", re.ASCII))
self.assertTrue(re.fullmatch(br".+\b", b"abc"))
self.assertTrue(re.fullmatch(br".+\b", b"abc", re.LOCALE))
self.assertTrue(re.fullmatch(r".+\b", "ьюя"))
self.assertIsNone(re.search(r"\b", "ьюя", re.ASCII))
# A non-empty string includes a non-boundary zero-length match.
self.assertTrue(re.search(r"\B", "abc"))
self.assertEqual(re.search(r"\B", "abc").span(), (1, 1))
self.assertEqual(re.search(r"\B", "abc", re.ASCII).span(), (1, 1))
self.assertEqual(re.search(br"\B", b"abc").span(), (1, 1))
self.assertEqual(re.search(br"\B", b"abc", re.LOCALE).span(), (1, 1))
self.assertEqual(re.search(r"\B", "ьюя").span(), (1, 1))
self.assertEqual(re.search(r"\B", "ьюя", re.ASCII).span(), (0, 0))
# There is no non-boundary match at the start of a string.
self.assertFalse(re.match(r"\B", "abc"))
self.assertIsNone(re.match(r"\B", "abc"))
self.assertIsNone(re.match(r"\B", "abc", re.ASCII))
self.assertIsNone(re.match(br"\B", b"abc"))
self.assertIsNone(re.match(br"\B", b"abc", re.LOCALE))
self.assertIsNone(re.match(r"\B", "ьюя"))
self.assertTrue(re.match(r"\B", "ьюя", re.ASCII))
# There is no non-boundary match at the end of a string.
self.assertIsNone(re.fullmatch(r".+\B", "abc"))
self.assertIsNone(re.fullmatch(r".+\B", "abc", re.ASCII))
self.assertIsNone(re.fullmatch(br".+\B", b"abc"))
self.assertIsNone(re.fullmatch(br".+\B", b"abc", re.LOCALE))
self.assertIsNone(re.fullmatch(r".+\B", "ьюя"))
self.assertTrue(re.fullmatch(r".+\B", "ьюя", re.ASCII))
# However, an empty string contains no word boundaries, and also no
# non-boundaries.
self.assertIsNone(re.search(r"\B", ""))
self.assertIsNone(re.search(r"\b", ""))
self.assertIsNone(re.search(r"\b", "", re.ASCII))
self.assertIsNone(re.search(br"\b", b""))
self.assertIsNone(re.search(br"\b", b"", re.LOCALE))
# This one is questionable and different from the perlre behaviour,
# but describes current behavior.
self.assertIsNone(re.search(r"\b", ""))
self.assertIsNone(re.search(r"\B", ""))
self.assertIsNone(re.search(r"\B", "", re.ASCII))
self.assertIsNone(re.search(br"\B", b""))
self.assertIsNone(re.search(br"\B", b"", re.LOCALE))
# A single word-character string has two boundaries, but no
# non-boundary gaps.
self.assertEqual(len(re.findall(r"\b", "a")), 2)
self.assertEqual(len(re.findall(r"\b", "a", re.ASCII)), 2)
self.assertEqual(len(re.findall(br"\b", b"a")), 2)
self.assertEqual(len(re.findall(br"\b", b"a", re.LOCALE)), 2)
self.assertEqual(len(re.findall(r"\B", "a")), 0)
self.assertEqual(len(re.findall(r"\B", "a", re.ASCII)), 0)
self.assertEqual(len(re.findall(br"\B", b"a")), 0)
self.assertEqual(len(re.findall(br"\B", b"a", re.LOCALE)), 0)
# If there are no words, there are no boundaries
self.assertEqual(len(re.findall(r"\b", " ")), 0)
self.assertEqual(len(re.findall(r"\b", " ", re.ASCII)), 0)
self.assertEqual(len(re.findall(br"\b", b" ")), 0)
self.assertEqual(len(re.findall(br"\b", b" ", re.LOCALE)), 0)
self.assertEqual(len(re.findall(r"\b", " ")), 0)
self.assertEqual(len(re.findall(r"\b", " ", re.ASCII)), 0)
self.assertEqual(len(re.findall(br"\b", b" ")), 0)
self.assertEqual(len(re.findall(br"\b", b" ", re.LOCALE)), 0)
# Can match around the whitespace.
self.assertEqual(len(re.findall(r"\B", " ")), 2)
self.assertEqual(len(re.findall(r"\B", " ", re.ASCII)), 2)
self.assertEqual(len(re.findall(br"\B", b" ")), 2)
self.assertEqual(len(re.findall(br"\B", b" ", re.LOCALE)), 2)

def test_bigcharset(self):
self.assertEqual(re.match("([\u2222\u2223])",
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