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bpo-34084: Fix setting an error message for the "Barry as BDFL" easter egg. by serhiy-storchaka · Pull Request #8262 · python/cpython · GitHub

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23 changes: 17 additions & 6 deletions Lib/test/test_flufl.py
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Original file line number Diff line number Diff line change
Expand Up @@ -4,18 +4,29 @@
class FLUFLTests(unittest.TestCase):

def test_barry_as_bdfl(self):
code = "from __future__ import barry_as_FLUFL; 2 {0} 3"
code = "from __future__ import barry_as_FLUFL\n2 {0} 3"

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Choose a reason Spam Abuse Off Topic Outdated Duplicate Resolved Low Quality

I am not familiar with compile. My question is when flags is passed, what's the meaning of the import here? Is it a must?

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Choose a reason Spam Abuse Off Topic Outdated Duplicate Resolved Low Quality

It is redundant if flags is passed.

The bug is that this tests is failed if not pass flags.

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Choose a reason Spam Abuse Off Topic Outdated Duplicate Resolved Low Quality

I know flags have to be passed. I just don't understand why not simply '2 {0} 3'?.

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Choose a reason Spam Abuse Off Topic Outdated Duplicate Resolved Low Quality

The intention of the test is that from __future__ import barry_as_FLUFL should change grammar. But this doesn't work, and we need to pass flags as a temporary workaround. After fixing this bug we could remove flags.

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gotcha. I wrongly thought the from __future__ import ... doesn't work in compile and flags must be passed.

compile(code.format('<>'), '<BDFL test>', 'exec',
__future__.CO_FUTURE_BARRY_AS_BDFL)
self.assertRaises(SyntaxError, compile, code.format('!='),
'<FLUFL test>', 'exec',
__future__.CO_FUTURE_BARRY_AS_BDFL)
with self.assertRaises(SyntaxError) as cm:
compile(code.format('!='), '<FLUFL test>', 'exec',
__future__.CO_FUTURE_BARRY_AS_BDFL)
self.assertRegex(str(cm.exception),
"with Barry as BDFL, use '<>' instead of '!='")
self.assertEqual(cm.exception.text, '2 != 3\n')
self.assertEqual(cm.exception.filename, '<FLUFL test>')
self.assertEqual(cm.exception.lineno, 2)
self.assertEqual(cm.exception.offset, 4)

def test_guido_as_bdfl(self):
code = '2 {0} 3'
compile(code.format('!='), '<BDFL test>', 'exec')
self.assertRaises(SyntaxError, compile, code.format('<>'),
'<FLUFL test>', 'exec')
with self.assertRaises(SyntaxError) as cm:
compile(code.format('<>'), '<FLUFL test>', 'exec')
self.assertRegex(str(cm.exception), "invalid syntax")
self.assertEqual(cm.exception.text, '2 <> 3\n')
self.assertEqual(cm.exception.filename, '<FLUFL test>')
self.assertEqual(cm.exception.lineno, 1)
self.assertEqual(cm.exception.offset, 4)


if __name__ == '__main__':
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3 changes: 1 addition & 2 deletions Parser/parsetok.c
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Original file line number Diff line number Diff line change
Expand Up @@ -246,8 +246,7 @@ parsetok(struct tok_state *tok, grammar *g, int start, perrdetail *err_ret,
else if ((ps->p_flags & CO_FUTURE_BARRY_AS_BDFL) &&
strcmp(str, "<>")) {
PyObject_FREE(str);
err_ret->text = "with Barry as BDFL, use '<>' "
"instead of '!='";
err_ret->expected = NOTEQUAL;
err_ret->error = E_SYNTAX;
break;
}
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4 changes: 4 additions & 0 deletions Python/pythonrun.c
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Original file line number Diff line number Diff line change
Expand Up @@ -1348,6 +1348,10 @@ err_input(perrdetail *err)
msg = "unexpected indent";
else if (err->token == DEDENT)
msg = "unexpected unindent";
else if (err->expected == NOTEQUAL) {
errtype = PyExc_SyntaxError;
msg = "with Barry as BDFL, use '<>' instead of '!='";
}
else {
errtype = PyExc_SyntaxError;
msg = "invalid syntax";
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