std::list::splice
cppreference.com
 [] |
Google. . , . , . |
![[]](https://upload.cppreference.com/mwiki/images/3/31/Imbox_notice.png){kind=link}
<metanoindex/>
<tbody> </tbody> void splice(const_iterator pos, list& other); |
(1) | |
void splice(const_iterator pos, list&& other); |
(1) | ( C++11) |
void splice(const_iterator pos, list& other, const_iterator it); |
(2) | |
void splice(const_iterator pos, list&& other, const_iterator it); |
(2) | ( C++11) |
void splice(const_iterator pos, list& other, const_iterator first, const_iterator last); |
(3) | |
void splice(const_iterator pos, list&& other, const_iterator first, const_iterator last); |
(3) | ( C++11) |
.
. , :
get_allocator() != other.get_allocator(). , *this, other.:
No elements are copied. The behavior is undefined if:
get_allocator() != other.get_allocator(). No iterators or references become invalidated, the iterators to moved elements now refer into *this, not into other.1)
other *this. , pos. other . , this == &other.:
Moves all elements from
other into *this. The elements are inserted before the element pointed to by pos. The container other becomes empty after the operation. The behavior is undefined if this == &other.2)
,
it other *this. , pos.:
Moves the element pointed to by
it from other into *this. The element is inserted before the element pointed to by pos.3)
[first, last) other *this. , pos. , pos [first,last).:
Moves the elements in the range
[first, last) from other into *this. The elements are inserted before the element pointed to by pos. The behavior is undefined if pos is an iterator in the range [first,last).| pos | ,
| |
| other | ,
| |
| it | ||
| first, last |
()
1-2)
.
3)
this == &other, std::distance(first, last).#include <iostream>
#include <list>
std::ostream& operator<<(std::ostream& ostr, const std::list<int>& list)
{
for (auto &i : list) {
ostr << " " << i;
}
return ostr;
}
int main ()
{
std::list<int> list1 = { 1, 2, 3, 4, 5 };
std::list<int> list2 = { 10, 20, 30, 40, 50 };
auto it = list1.begin();
std::advance(it, 2);
list1.splice(it, list2);
std::cout << "list1: " << list1 << "\n";
std::cout << "list2: " << list2 << "\n";
list2.splice(list2.begin(), list1, it, list1.end());
std::cout << "list1: " << list1 << "\n";
std::cout << "list2: " << list2 << "\n";
}
:
list1: 1 2 10 20 30 40 50 3 4 5
list2:
list1: 1 2 10 20 30 40 50
list2: 3 4 5
.
| (public -) | |
| , (public -) |