std::copy_backward
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<tbody> </tbody>| Dclar dans l'en-tte <algorithm>
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template< class BidirIt1, class BidirIt2 > BidirIt2 copy_backward( BidirIt1 first, BidirIt1 last, BidirIt2 d_last ); |
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Copie les lments de la gamme, dfinie par
[first, last), une autre plage qui se termine d_last. Les lments sont copis dans l'ordre inverse (le dernier lment est copi d'abord), mais leur ordre relatif est prserv .Original:
Copies the elements from the range, defined by
[first, last), to another range ending at d_last. The elements are copied in reverse order (the last element is copied first), but their relative order is preserved.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Paramtres
| first, last | - | l'intervalle des lments copier
Original: the range of the elements to copy The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| d_last | - | fin de la plage de destination. Si
d_last est dans [first, last), std::copy doit tre utilis la place de std::copy_backward . Original: end of the destination range. If d_last is within [first, last), std::copy must be used instead of std::copy_backward. The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| Type requirements | ||
-BidirIt must meet the requirements of BidirectionalIterator.
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Retourne la valeur
itrateur sur le dernier lment copi .
Original:
iterator to the last element copied.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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Complexit
Exactement
last - first missions .Original:
Exactly
last - first assignments.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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Mise en uvre possible
template< class BidirIt1, class BidirIt2 >
BidirIt2 copy_backward(BidirIt1 first, BidirIt1 last, BidirIt2 d_last)
{
while (first != last) {
*(--d_last) = *(--last);
}
return d_last;
}
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Exemple
#include <algorithm>
#include <iostream>
int main()
{
std::vector<int> from_vector;
for (int i = 0; i < 10; i++) {
from_vector.push_back(i);
}
std::vector<int> to_vector(15);
std::copy_backward(from_vector.begin(), from_vector.end(), to_vector.end());
std::cout << "to_vector contains: ";
for (unsigned int i = 0; i < to_vector.size(); i++) {
std::cout << to_vector[i] << " ";
}
}
Rsultat :
to_vector contains: 0 0 0 0 0 0 1 2 3 4 5 6 7 8 9
Voir aussi
(C++11) |
Copie une srie d'lments vers un nouvel emplacement Original: copies a range of elements to a new location The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (fonction gnrique) |