std::set_intersection
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<tbody> </tbody>| Dclar dans l'en-tte <algorithm>
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template< class InputIt1, class InputIt2, class OutputIt > OutputIt set_intersection( InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first ); |
(1) | |
template< class InputIt1, class InputIt2, class OutputIt, class Compare > OutputIt set_intersection( InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first, Compare comp ); |
(2) | |
Construit une gamme dbutant tris
d_first constitu d'lments que l'on retrouve dans les deux gammes tris [first1, last1) et [first2, last2). La premire version prvoit la fois d'entre se situe trier avec operator<, la deuxime version s'attend ce qu'ils soient tris la comp fonction de comparaison donne. Si un lment est trouv m fois en [first1, last1) et n fois dans [first2, last2), les lments std::min(m, n) premiers seront copis partir de la premire plage la plage de destination. L'ordre des lments quivalents est prserve. La gamme rsultante ne peut pas faire double emploi avec l'une des plages d'entre .Original:
Constructs a sorted range beginning at
d_first consisting of elements that are found in both sorted ranges [first1, last1) and [first2, last2). The first version expects both input ranges to be sorted with operator<, the second version expects them to be sorted with the given comparison function comp. If some element is found m times in [first1, last1) and n times in [first2, last2), the first std::min(m, n) elements will be copied from the first range to the destination range. The order of equivalent elements is preserved. The resulting range cannot overlap with either of the input ranges.The text has been machine-translated via Google Translate.
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Paramtres
| first1, last1 | - | la premire gamme d'lments examiner
Original: the first range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| first2, last2 | - | la seconde plage d'lments examiner
Original: the second range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| comp | - | comparison function which returns true if the first argument is less than the second. The signature of the comparison function should be equivalent to the following:
The signature does not need to have |
| Type requirements | ||
-InputIt1 must meet the requirements of InputIterator.
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-InputIt2 must meet the requirements of InputIterator.
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-OutputIt must meet the requirements of OutputIterator.
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Retourne la valeur
Iterator-del de la fin de la gamme construit .
Original:
Iterator past the end of the constructed range.
The text has been machine-translated via Google Translate.
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Complexit
A comparaisons plupart 2·(N1+N2-1), o N1
= std::distance(first1, last1) et N2 = std::distance(first2, last2) .Original:
At most 2·(N1+N2-1) comparisons, where N1
= std::distance(first1, last1) and N2 = std::distance(first2, last2).The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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Mise en uvre possible
| First version |
|---|
template<class InputIt1, class InputIt2, class OutputIt>
OutputIt set_intersection(InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2,
OutputIt d_first)
{
while (first1 != last1 && first2 != last2) {
if (*first1 < *first2) {
++first1;
} else {
if (!(*first2 < *first1)) {
*d_first++ = *first1++;
}
++first2;
}
}
return d_first;
}
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| Second version |
template<class InputIt1, class InputIt2,
class OutputIt, class Compare>
OutputIt set_intersection(InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2,
OutputIt d_first, Compare comp)
{
while (first1 != last1 && first2 != last2) {
if (comp(*first1, *first2)) {
++first1;
} else {
if (!comp(*first2, *first1)) {
*d_first++ = *first1++;
}
++first2;
}
}
return d_first;
}
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Exemple
#include <iostream>
#include <vector>
#include <algorithm>
#include <iterator>
int main()
{
std::vector<int> v1{1,2,3,4,5,6,7,8};
std::vector<int> v2{ 5, 7, 9,10};
std::sort(v1.begin(), v1.end());
std::sort(v2.begin(), v2.end());
std::vector<int> v_intersection;
std::set_intersection(v1.begin(), v1.end(),
v2.begin(), v2.end(),
std::back_inserter(v_intersection));
for(int n : v_intersection)
std::cout << n << ' ';
}
Rsultat :
5 7
Voir aussi
calcule l'union de deux ensembles Original: computes the union of two sets The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (fonction gnrique) | |