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    std::copy_n

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    <tbody> </tbody>
    Dclar dans l'en-tte <algorithm>
    template< class InputIt, class Size, class OutputIt > OutputIt copy_n( InputIt first, Size count, OutputIt result );
    Copie exactement count valeurs du dbut de la plage first au dbut de la plage result, si count>0. Ne fait rien autrement .
    Original:
    Copies exactly count values from the range beginning at first to the range beginning at result, if count>0. Does nothing otherwise.
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    Paramtres

    first -
    le dbut de la srie d'lments copier
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    the beginning of the range of elements to copy from
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    count -
    nombre d'lments copier
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    number of the elements to copy
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    result -
    le dbut de la plage de destination
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    the beginning of the destination range
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    Type requirements
    -
    InputIt must meet the requirements of InputIterator.
    -
    OutputIt must meet the requirements of OutputIterator.

    Retourne la valeur

    Iterator dans la plage de destination, pointant aprs le dernier lment copi ou si count>0 first autrement .
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    Iterator in the destination range, pointing past the last element copied if count>0 or first otherwise.
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    Complexit

    Exactement count missions, si count>0 .
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    Exactly count assignments, if count>0.
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    Mise en uvre possible

    template< class InputIt, class Size, class OutputIt>
OutputIt copy_n(InputIt first, Size count, OutputIt result)
{
    if (count > 0) {
        *result++ = *first;
        for (Size i = 1; i < count; ++i) {
            *result++ = *++first;
        }
    }
    return result;
}

    Exemple

    #include <iostream>
#include <string>
#include <algorithm>
#include <iterator>

int main()
{
    std::string in = "1234567890";
    std::string out;

    std::copy_n(in.begin(), 4, std::back_inserter(out));
    std::cout << out << '\n';
}

    Rsultat : 

    1234

    Voir aussi


    (C++11)
    Copie une srie d'lments vers un nouvel emplacement
    Original:
    copies a range of elements to a new location
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    (fonction gnrique) [edit]
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